8(2^x+4)=128

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Solution for 8(2^x+4)=128 equation: 



8(2^x+4)=128

We move all terms to the left:

8(2^x+4)-(128)=0

We multiply parentheses

16x+32-128=0

We add all the numbers together, and all the variables

16x-96=0

We move all terms containing x to the left, all other terms to the right

16x=96

x=96/16

x=6

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